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Sagot :
When sodium methoxide and 2-bromo-2-methylbutane combine in methanol, the anticipated main result is (C) 2-Methylbut-2-ene
In the first stage, 2-bromo-2-methylbutane dissociates, removing bromide, and forms 2-bromo-2-methylbutane by a carbocation.
C4C+H11 + Br = C5H11Br
Sodium methoxide then interacts with this carbocation. Two products will be produced by this reaction: 2-methyl-but-2-ene and 2-methyl-but-1-ene. The main product will be 2-methyl-but-2-ene among them. Methanol is utilized as a solvent in this process.
Na+ + C4C+H11 + C2H5O CH3-CCH3=CH-CH3 + CH2=CCH3-CH2-CH3
Therefore, 2-Methylbut-2-ene will result in a significant product from the reaction (C).
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