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replace the loading by an equivalent resultant force and couple moment acting at point o

Sagot :

The equivalent resultant couple moment about the point O is 15.375KNm

The load carried by section (1)

F1 = 1/2 × 1.5 × (w1 - w2)

F1 = 1/2 × 1.5 × 4 = 3KN

the load carried by section (2).

F2 = w2 × (1.5 + 0.75)

F2 = 4 × 2.25 = 9KN

F3 = 1/2 × 0.75 × 4 = 1.5 KN

Determine the equivalent resultant force.

∑Fr = F1 + F2 + F3 = 13.5 KN

the moment about the point O due to distributed loading,

∑ Mr = F1 x1 + F2x2 + F3x3

x1 = 0.5m

x2 = 1.125m

x3 = 2.5m

the equivalent resultant couple moment about the point O is

Mr = ∑Mr = 15.375KNm

The equivalent resultant couple moment about any point on the given beam is equal to the sum of couple moment developed by each of the distributed loading about that point. Calculate the moment caused by each force about point O, using the distance of the centroid from end O.

Learn more about couple moment here:

https://brainly.com/question/15015715

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