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find the curvature of r(t) at the point (7,1,1), r(t)=<7t,t2,t3>

Sagot :

The equation for curvature is given by κ = |r' × r''|/|r'|3 where r' = dr/dt and r'' = d2r/dt2. the curvature of r(t) at the point (7,1,1), r(t)=<7t,t2,t3> is √14/√490.

The equation for curvature is given by κ = |r' × r''|/|r'|3 where r' = dr/dt and r'' = d2r/dt2.

We are given the point (7,1,1) which is the same as t=1.

Therefore, we can substitute t=1 into the function r(t) to obtain r(1) =<7,1,1>.

From this, we can calculate the derivatives r' and r'' of the function r(t) at the point (7,1,1).

r' = <7,2,3>

r'' = <0,2,6>

Then, we can calculate the curvature κ using the equation κ = |r' × r''|/|r'|3.

κ = |<7,2,3> × <0,2,6>|/|<7,2,3>|3

= |<0,-14,18>|/|<7,2,3>|3

= √14/√490

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