Find trusted answers to your questions with the help of IDNLearn.com's knowledgeable community. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.
Sagot :
(a) ball velocity = - 2.47 m/s
(b) block velocity = 1.236 m/s
What is collision?
Two items collide when they briefly come into touch with one another. To put it another way, a collision is a brief reciprocal encounter between two masses in which the momentum and energy of the masses change.
For ball as it is at initially at height of 70.0 cm = 0.7 m
so by energy conservation,
K.E.(i) P.E.(i) + K.E.(f)+P.E.(f)
0 + mg×(0.7) = 1/2 mv² + 0
v = 3.71 m/s
now, collision b/w ball and block
as the block is in rest initially and there is no external force b/w them
so by momentum conservation,
m₁u₁+ m₂u₂ = m₁v₁+ m₂v₂
or, (0.5 x 3.71) + 0 = (0.5x v₁) + (2.5 x v₂)
3.71 = v₁ + 5v₂ .........(1)
as elastic collision so energy conservation
or, 1/2 m₁ u₁² + 1/2 m₂ u₂² = 1/2 m₁ v₁² + 1/2 m₂ v₂²
or, (1/2 x 0.5 x 3.712) + 0 = (1/2 x 0.5 x v₁²) + (1/2 x 2.5 x v₂²)
or, 3.433 = 0.25xv₁² + 1.25 v₂² ...............(2)
from eq. 1 and eq. 2
or, 3.433 = 0.25 x (3.71 - 5 v₂)² + 1.25v₂²
or, v² = 1.236 m/s
and v₁ = 3.71 - 5v₂
or, v₁ = - 2.47 m/s
so after collision
ball velocity = - 2.47 m/s [(-)ve x direction]
block velocity = 1.236 m/s [(+)ve x direction]
To know more about velocity refer to:
https://brainly.com/question/24445340
#SPJ1
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.
