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A 20.0cm massless spring with spring constant 340N/m is suspended from the ceiling. A student carefully hangs a 450g mass from the free end. How long is the spring now?

Sagot :

After hanging the mass, the length of the spring is 21.3 cm using Hooke's law.

What is Hooke's law?

According to the physics principle known as Hooke's Law, the force required to expand or compress a spring by a given distance is inversely proportional to that distance.

The first traditional example of an explanation of elasticity is Hooke's law. Elasticity is the quality of a substance or item that allows it to return to its original shape after distortion. A restoration force is a capacity to restore the original shape after experiencing distortion.

Given,

Equilibrium length of the massless spring = 20 cm

Spring constant k = 340 N/m

The spring is suspended from the ceiling.

Mass at the free end = 450 g

= 0.45 kg

A force is applied vertically downward on the spring due to the suspended mass which is equivalent to the weight of the mass i.e.

F = mg             ... (1)

This force is balanced by the spring. If the spring is extended by a length of  due to the suspension of the mass then by Hooke's law,

F = kx              ... (2)

From equation (1) and (2)

mg = kx

x = mg/k

Put all the values

x = (0.45)(9.8)/(340)

= 0.013 m

= 1.3 cm

So, the length of the spring is

l = 20 + 1.3

= 21.3 cm

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