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aspurpinion has 17 teeth and a diametral pitch of 8 teeth/in. it runs at 1120 rpm and drives a gear at 544 rpm. find the number of teeth on the gear and the distance between the centers of the pinion and gear

Sagot :

Theoretical centre-to-centre distance (C)=3.25 which is the distance between the centers of the pinion and gear

Given data:

No. of teeth on the pinion(TP)=17.

Diametral pitch(pd)=8 teeth/in.

The rotational speed of the pinion(NP)=1120 rev/min or 1120 rpm.

The rotational speed of the gear(NG)=544 rev/min or 544 rpm.

To calculate:

No. of teeth on gear(TG) & theoretical centre-to-centre distance(C).

We know that;

Diametral pitch(pd)=No. of teeth in the gear/Diameter of the gear

For pinion,

pd=TP/DP

Pittiong the values in above eq.

8 teeth/in =17/DP =>DP=17/8 in.

or DP=2.125 in.

Gear ratio(G)=(NP/NG)=(TG/TP)=(DG/DP)

(NP/NG)=(TG/TP)

1120/544 =TG/17 =>TG=35

therefore No. of teeth the gear(TG)=35 {Ans}

Also from gear ratio formula,

(NP/NG)=(DG/DP)

1120/544=DG/2.125

DG=4.375 in.

In figure I have drawn a rough diagram of the pinion and gear arrangement which will help you to understand how to calculate the centre-to-centre distance(C)

From fig.,

centre to centre distance,C=rP+rG {Where rP and rG are the radii of pinion and gear respectively}

C=(DP+DG)/2 {\large \because Diameter =2*radius}

C=(2.125+4.375)/2 in. =3.25 in.

therefore Theoretical centre to centre distance (C)=3.25

To learn more about centre to centre distance

https://brainly.com/question/11878555

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