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Sagot :
The distance falls by the object in 3 seconds is 88.2 meters
The distance that an object falls when it is dropped is directly proportional to the square of the amount of time
Consider the distance as d and the time as t
Then the relationship will be
d ∝ t^2
d = kt^2
The distance falls in 2 seconds = 39.2 meters
Substitute the values in the equation
39.2 = k × 2^2
39.2 = 4k
k = 39.2 /4
k = 9.8
When the time = 3 seconds
The distance = 9.8 × 3^2
= 9.8 × 9
= 88.2 meters
Therefore, the object fall 88.2 meters in 3 seconds
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