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The probability that the flight is less than 71 minutes is 0.1471
Let the distribution of the time to fly between New York City and Chicago be X
X~U(66,100)
where,
66 = minimum
100 = maximum
We need to find P(X<71)
We know that in the case of uniform distribution,
P(X<x) = (x - a) / b -a
where,
a = min value
b = max value.
Hence P(X<71)
= (71 - 66) / (100 - 66)
= 5/34
= 0.1471
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