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Sagot :
The total maximum area enclosed by both the shapes square and a circle using given wire is equal to 2.27 square feet.
As given in the question,
Let 'x' be the side length of the square
And 'r' be the radius of the circle.
Length of the wire = 4 feet
Maximum side length of the square is:
4x = 4
⇒ x = 1feet
Maximum area of the square = x²
= 1²
= 1
Maximum radius of the circle is:
2πr = 4
⇒ r = 2 / π
Maximum area of the circle = πr²
= π × (2/π)²
= 4 / π
Total maximum area enclosed by square and a circle
= 1 + (4/π)
= 1 + 1.27
= 2.27 square feet.
Therefore, the total maximum area enclosed by square and a circle from the given wire is equal to 2.27 square feet.
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