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Sagot :
116 N
The initial potential energy of the child is given by:
[tex]U_{i} =mgh[/tex]
[tex]U_{i} =31[/tex]×[tex]9.8[/tex]×3 = 911.4 J
There is no change in kinetic energy since the child is sliding down at a steady speed (because the speed remains constant). When the child reaches the bottom of the slide, the height is h=0 and the gravitational potential energy is [tex]U_{f}[/tex]=0, hence there is a change in the gravitational potential energy. Consequently, the energy variation is
Δ[tex]E[/tex]=ΔU= 0-911.4 = -911.4J
So, there have been a loss of energy. This energy loss is equal to the work done by the friction, which is given by:
W=-Fd
where F is the magnitude of the force of friction, d=7.8 m is the length of the slide ,the negative sign is due to the fact that the friction is opposite to the motion of the child
On Substituting, we get
-911.4=-Fd
∴F= [tex]\frac{911.4}{7.8}[/tex]
F=116N
To learn more about Kinetic Friction here :https://brainly.com/question/11574957
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