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Sagot :
The slope of the line perpendicular to the line with given equation is equal to -2/3.
The equation of the line is 2y = 3x - 1 and if we write this in slope intercept form then we write it as
2y = 3x - 1
dividing by 2 on both sides we get
y = 3/2x - 1/2
Slope of this line is m = 3/2. Now the slope of line perpendicular to this will be equal to -1/m that is equal to -2/3.
For second part,
If we translate the graph y = |x| to two units left, then we get the expression as y = |x + 2|. The graph of this attached below.
Now, the equation of line that has an undefined slope and passes through the point (4, 7) is expressed as
(y - 7) = 1/0(x - 4)
0 = x - 4
=> x = 4
Now, to calculate slope of line passing through two points (x₁, y₁) and (x₂, y₂) we use the formula
m = (y₂ - y₁)/(x₂ - x₁)
m = (7 - 5)/(1 + 3)
m = 2/4
m = 1/2
Now, the equation of line that has a slope of -5 and passes through the point (0, 2) is expressed as
(y - 2) = -5(x -0)
y - 2 = -5x
y = -5x + 2
Now, a point having a negative abscissa and negative ordinate is in quadrant III.
Now, if y is 6 when x is 3 and y varies directly with x then it means that y is two times that of x. This means that when x is 8, then the value of y is equal to 16.
Learn more about Slope at:
brainly.com/question/3493733
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