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Sagot :
The equation of line passing through point (6, 8) is equal to (y - 8) = m(x - 6) where m is the slope..
If we need to find the equation between two points (x₁, y₁) and (x₂, y₂), we use the formula
(y - y₁) = m(x - x₁); where m is the slope which is expressed as
m = (y₂ - y₁)/(x₂ - x₁)
Since for the first we don't have the second point so we assume the slope as 'm' and the Equation will be
(y - 8) = m(x - 6)
Now, the points are (0, 1) and (5, 3)
m = (3 - 1)/(5 - 0)
m = 2/5
Equation will be: (y - 1) = 2/5(x - 0)
=> 5y = 2x + 5
Now, the points are (-2, 2) and (0, 5)
m = (5 - 2)/(0 + 2)
m = 3/2
Equation will be: (y - 2) = 3/2(x + 2)
=> 2y = 3x + 10
Now, the points are (5, 0) and (-8, 0)
m = (0 - 0)/(-8 - 5)
m = 0
Equation will be: (y - 0) = 0(x - 5)
=> y = 0
Learn more about Slope at:
brainly.com/question/3493733
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