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Sagot :

equation of straight line passing through P(0,0) and Q(5,2) is

2x - 5y = 0;

let there be 2 points as P(0,0) and Q(5,2)

Then the equation of the straight line is

Using two-point form:

(y - 0) = (2 - 0)/(5 - 0) (x-0);

y = 2/5 x

cross multiplying

5y = 2x

2x - 5y = 0;

slope of line passing through point R(2,5) and (0,-4)

m = 5-(-4)/2-0

m = 9/2;

the slope of line passing through points S(2,5) and T(1,4)

m = 5-4/2-1

m = 1;

Slope of line passing through L(-9,6) and M(-3,9)

m = 9 - 3/ -3 - (-9)

m = 6/ -3 + 9

m = 6/6

m=1;

Learn more about Equation of straight line at:

brainly.com/question/28951560

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