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what are the zeros of the polynomial y=3(x+4)(x+1)(x-3) a) -4

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The zeroes of the given Polynomial equation; y=3 (x+4) (x+1) (x-3) are; -4, -1 and 3.

What are the zeroes of the given Polynomial equation?

It follows from the task content that the zeroes of the given polynomial equation are to be determined.

Recall that the zeroes of a polynomial equation can be determined by equating all of the factors of the polynomial to zero.

Since the given Polynomial is; y=3(x+4)(x+1)(x-3).

The zeroes are as follows;

  • x + 4 = 0; x = -4.
  • x + 1 = 0; x = -1.
  • x - 3 = 0; x = 3.

On this note, it can be concluded that the zeroes of the polynomial as required are; -4, -1 and 3.

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