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What is the mass of 22.4 L of gas at STP is?

Sagot :

The mass of 22.4 L of gas at STP is calculated by the moles multiplied by the molar mass. and is equal to the molar mass of the gas.

According to the ideal gas equation , the expression is given as :

P V = n R T

n = P V / R T

pressure P is 1 atm

The volume V is 22.4 L

the gas constant R is 0.0823 at L / mol K

the temperature is 273 K

so, the number of moles at STP is given as :

n = P V / R T

n = ( 1 × 22.4 ) / ( 0.0823 × 273 )

n = 1 mole

the number of moles is given as :

moles = mass / molar mass

mass = moles × molar mass

mass = 1 mol × molar mass in g /mol

mass = molar mass in g /mol

To learn more about moles here

https://brainly.com/question/20486415

#SPJ4

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