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What is the momentum of a photon of a laser beam of wavelength 632.8 A?

Sagot :

The momentum of each photon in the light beam is 1.046×10⁻²⁷ kgms⁻¹

λ= 632.8nm=632×10⁻⁹ m

Power, P=9.42mW=9.42×10 ⁻³W

Energy of each photon in the light beam,

E= (hc)/λ​ =

(6.6×10 ⁻³⁴×3×10 ⁸) / 632.8×10⁻¹⁹ = 3.14×10 ⁻¹⁹ = (3.14×10 ⁻¹⁹)/1.6 x 10⁻¹⁹

= 1.963ev

The momentum of each photon in the light beam,

p = h/λ = (6.6×10 ⁻³⁴)/(632×10⁻⁹ ) = 1.046×10⁻²⁷ kgms⁻¹

Momentum is a measurement of mass in motion: how much mass is in how much motion. It is usually given the symbol p. Where m is the mass and v is the velocity.

Example - Whenever you toss a ball at someone as well as it smacks him square in the face. It indicates how difficult it would have been to stop the thing. A baseball is swooping through the air. A large truck is moving. A bullet discharged from such a firearm.

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