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THE GRAPH IS ATTACHED ALONG WITH THIS
The parabola has a minima, vertex and a y-intercept.
Given,
Since the equation is quadratic, the parabola has a vertex. To find it, do as follows:
x = -b/2a
Where:
a=1
b=-2
Then:
x = -(-2)/ 2 × 1 = 1
Substitute this into the equation to obtain y:
y = 1² - 2 × 1 + 3 = 2
The point of the vertex is (1,2)
The sign of a is positive, therefore, the parabola has a minimum.
Substitute x=0 into the equation to find y-intercept:
y = 0² - 2 × 0 + 3
y = 3
You know that this point is (0,3)
Recognize that the parabola has a minimum, a vertex, and a y-intercept, and that you may graph it as shown in the accompanying image.
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