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Sagot :
The equation of a line that passes through [tex](-1,3)[/tex] and has a slope [tex]2[/tex] is [tex]y=2x+5[/tex]
The equation of the line passes through the point is [tex](-1,3)[/tex]
One point and the slope are given, we will use one point form i.e.
[tex]y=mx+c.....(1)[/tex]
The point [tex](-1,3)[/tex] satisfies the equation and the slope is [tex]2[/tex]
Plug in these values in (1)
[tex]3=2(-1)+c\\3=-2+c\\c=3+2\\c=5[/tex]
Plug in the value of slope and c is
The equation becomes [tex]y=2x+5[/tex]
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