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the equation of the line that passes through the points − 1/3 and 1 11 is
y = 3x + 8 with slope 12 1/3.
1. Find the slope of the line.
m = (11 - -1/3) / (1 - -1/3)
m = 12 1/3
2. Using the point-slope equation, substitute the slope and one point from the line
y - y1 = m(x - x1)
y - -1/3 = 12 1/3 (x - (-1/3))
3. Solve for y
y = 12 1/3x + 8
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