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Write the electron configuration for a neutral atom of selenium!

Sagot :

The electronic configuration of neutral atom of selenium is

           1s2 2s2 2p6 3s2 3p6 3d10 4s2  4p4.

Chemical element selenium has the symbol Se and its atomic number is 34. It comes in the category of non-metals. Selenium consists of 34 electrons distribution in its 4 orbits. Valence electrons are the electrons which are located in the outermost shell of the atom or molecule. Selenium has 6 electrons in its outermost shell

So electronic configuration of selenium define as:

     1s2 2s2 2p6 3s2 3p6 3d10 4s2  4p4.

The neutral atom in selenium is Ar. so, The electronic configuration of Argon  is represented as ,

        1s2 2s2 2p6 3s2 3p6

The number of valence electrons is defined as the number of electrons present in the outermost shell of the atom. So, in the case of selenium, there are 6 valence electrons. so, like this we can write the electronic configuration of selenium.

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