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A sled of mass 8 kg slides along the ice. It has an initial speed of 4 m/s but stops because of friction. How much work is done by friction?.

Sagot :

Ayuneidn

The work done by the friction force on the 8-kg sled is 64 Joule.

The work done by a force on an object is given by:

W = F . s

Where:

F = force

s = distance

Using the equation of motion:

v² = u² - 2 as

where:

v = final speed

u = initial velocity

a = acceleration

In this case v = 0 since the sled finally stops.

Hence,

0 = 4² - 2 as

2 as = 16

as = 8

Using the Newton's 2nd law of motion:

F = m . a

Where:

m = mass of the sled = 8

Substitute F = m . a into the work equation:

W = m . as

Substitute m = 8 and as = 8,

W = 8 x 8 = 64 Joule

Hence, the amount of work done is 64 Joule.

Learn more about work here:

https://brainly.com/question/25816840

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