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What is the average rate of change of the function on the interval from x = 0 to x = 5? f(x)=12(3)x.

Sagot :

the average rate of change of the function on the interval from x = 0 to x = 5 is 580.8

Average rate of change of a function f(x) between x-values x1 and x2 = (f(x2) -f(x1)/ (x2 -x1)

For this given function f(x)=12(3)x then it will mean that

f(x) = 12.3^x and x-values 0 and 5, the average rate of change is

the average rate of change = (f(5) -f(0))/(5 -0) = (2916 -12)/5 = 580.8

Learn more about the average rate of change of the function here: https://brainly.com/question/24313700

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