From tech troubles to travel tips, IDNLearn.com has answers to all your questions. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.
Sagot :
The standard enthalpy change for the reaction 2H2O (l) → 2H2 (g) + O2 (g) is -873.6 kJ/mol.
The standard enthalpy change (ΔH°) for a reaction is the enthalpy change when all reactants and products are in their standard states (at 1 atm pressure and a specified temperature, usually 25°C).
The standard enthalpy change for the reaction 2H2O (l) → 2H2 (g) + O2 (g) can be calculated using the standard heats of formation of the reactants and products as follows:
ΔH°rxn = [ΔH°f (H2O, l) x 2] + [ΔH°f (H2, g) x 2] + ΔH°f (O2, g)
ΔH°rxn = [-285.8 kJ/mol x 2] + [-241.8 kJ/mol x 2] + 0 kJ/mol
ΔH°rxn = -873.6 kJ/mol
Therefore, the standard enthalpy change for the reaction 2H2O (l) → 2H2 (g) + O2 (g) is -873.6 kJ/mol.
For more questions like Enthalpy change click the link below:
https://brainly.com/question/20910072
#SPJ4
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.