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A 925 kg car rounds an unbanked curve at a speed of 25 m/s. If the radius of the curve is 72 m, what is the minimum coefficient of friction between the car and the road required so that the car does not skid?.

Sagot :

The minimum coefficient of friction required is 0.885  for a 925kg car rounds an unbanked curve at a speed of 25m/sec.

We know that if a body wants to travel from one place to another place, we need friction to move along the surface.

Now,we know that centripetal force is required to move along a curve.Also,due to friction same amount of force acts on the car to move along the surface.

It means centripetal force=mv²/r where v is the velocity of the body and r is the radius of the body is equal to force applied by the friction which is equal to =μmg  

So,mv²/r=μmg  

=>v²/r =μg

=>μ= v²/rg

On putting the values of speed, radius and acceleration due to gravity

=>μ=(25)²/(72×9.8)

=>μ=625/705.6

=>μ=0.885

Hence, required value of coefficient of friction is 0.885.

To know more about coefficient of friction, visit here:

https://brainly.com/question/13828735

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