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on the moon, the acceleration due to gravity is -1.6 meters per second per second. a stone is dropped from a cliff on the moon and hits the surface of the moon 28 seconds later. how far did it fall? (round your answer to one decimal place.)

Sagot :

a) - 627.7 m

b) - 44.8 m/s

a) we use the formula,

d = gt²/2

when we substitute the values,

d = -1.6 X 28²/2

= -1.6 X 784/2

= - 627.2m

distance travelled by the stone was - 627.2m

b) calculate the impact,

v = gt

substitute,

v = (-1.6) X 28

v = - 44.8 m/s

The negative sign here indicates that the object is going down.

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