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a buffer solution contains 0.301 m khco3 and 0.288 m k2co3. if 0.0273 moles of sodium hydroxide are added to 125 ml of this buffer, what is the ph of the resulting solution ? (assume that the volume does not change upon adding sodium hydroxide)

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The pH of the resulting solution is 9.96 that can be calculated by using the using the pOH values.

Buffer Solution is a water solvent primarily based totally answer which includes a combination containing a vulnerable acid and the conjugate base of the vulnerable acid, or a vulnerable base and the conjugate acid of the vulnerable base. They face up to a alternate in pH upon dilution or upon the addition of small quantities of acid/alkali to them.

Millimoles of NH3 = 0.316 x 250 = 79

Millimoles of NH4Br = 0.339 x 250 = 84.75

Millimoles of KOH = 57.3

pOH  = pKb + log [salt - C / base + C]

       = 4.74 + log [84.75 - 57.3 / 79 + 57.3]

      = 4.04

pH + pOH=14

pH=14-4.04

pH = 9.96

To learn more about pH check the link below:

https://brainly.com/question/172153

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