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Sagot :
The equation for circle is 28g + 16f =260
and the equation of tangent to this circle is y = [tex]\frac{6}{12}[/tex] x +29
a) the main equation of circle is ax + by +2gx+ 2fy +c =0 --------- (1)
Now,
putting the points (0,0) , (0,8) and (6,12) one by one, we get,
For the point (0,0), we get:
c =o ----------------------------- (2)
For the point (6,12), we get:
6x +12y + c = (6)² + (12)²
⇒ 6x +12y +c = 36 +144
⇒ 6x +12y +c = 180 --------------------------- (3)
For the point (0,8), we get,
8y + c = 64 ----------------------------- (4)
putting c=0,
8y +0 = 64
⇒ y =64/8
⇒ y = 8
Putting c=0 and y =8, we get,
6x + 12×8 +0 = 180
⇒ 6x + 96 =180
⇒ 6x = 84
⇒ x = 14
Putting all the values in equation (1), we get:
(14)² + (8)² +28g +16g + 0 = 0
⇒ 196 + 64 + 28g +16f =0
⇒ 28g + 16f = 260
b) As we know the tangent from the circle:
y = mx + c
⇒ 8 = -12/6 × 14 +c
⇒ c = 29
Therefore, the equation of the tangent is y = [tex]\frac{6}{12}[/tex]x + 29
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