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What is the turning point of the graph of f(x) = |x – 4| ?
For [tex]x<4[/tex] [tex]f'(x)<0[/tex]. For [tex]x>4[/tex] [tex]f'(x)>0[/tex]. [tex]\Downarrow\\
[/tex] At [tex]x=4[/tex] there's turning point, which is equal [tex]|4-4|=|0|=0[/tex].
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