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what is the steps to this problem y=6x-11 -2x-3y=-7

Sagot :

[tex] \left \{ {{y=6x-11} \atop {-2x-3y=-7}} \right. \ \ \ | substitute\ first\ equation\ into \ the\ second\\\\ -2x-3(6x-11)=-7\\\\ -2x-18x+33=-7\\\\ -20x+33=-7\ \ \ | subtract\ 33\\\\ -20x=-40\ \ \ | divide\ by\ -20\\\\ x=2\\\\ y=6x-11=6*2-11=12-11=1[/tex]
just subsitute 6x-11 for y in the second equation
-2x-3(6x-11)=-7
-2x-18x+33=-7
-20x+33=7
subtract 33 from both sides
-20x=-40
multiply -1
20x=40
dividede by 20
x=2

then subsitute
y=6x-11
y=6(2)-11
y=12-11
y=1

x=2
y=1