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Josh has been running for 6 min and completes a lap in 7 min. Gabe has been running for 2 min and completes a lap in 9 min.
How many more laps must Josh and Gabe complete to have run the same amount of time?
so j completed 6/7 of a lap gabe has completed 2/9 lap so 1 j lap=7 mins s o 7j j=num of laps 1 g lap=9 mins so 9g g=num of laps then 6+j and g+2
so when will the times be equal 7j+6=9g+2 subtract 2 from both sides 7j+4=9g divide both sides by 9 7/9j+4/9=g so to get a whole number of laps, we must subsitute a number when it is multiplied by 7 then add 4, we get a multiplue of 9 so if j=2 7/9(2)+4/9=g=14/9+4/9=g=18/9=g=2 so josh and gabe must run 2 lap each because 6+(2 times 7)=2+(9 times 2) 6+14=2+18 20=20 true so
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