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a ball is dropped from rest at a height of 80 m above the ground. what is the speed just as it hits the ground?
Δx=Vi(t)+.5at² Δx=80 a=9.8 Vi=0 since its from rest, the initial velocity is 0. 80=0+.5(9.8)t² t=16.33 You can use one of the big five equations: Vf=Vi+at Vf=0+9.8(16.33) Vf=160.034 m/s
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