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write an equation in general form of the line passing through (3, -5) whose slope is the negative reciprocal of -1/4
negative reciprocal means -1/4 times x=-1 solve for x multiply both sides by -4/1 x=-4 so slope=-4 y=mx+b m=slope, b=y intercpet y=-4x+b input 3 for x and -5 for y -5=-4(3)+b -5=-12+b add 12 to both sides 7=b the equation in slope intercept form is y=-4x+7 that is my standard form another standard form is y+4x=7
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