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WRITE EQUATION OF THE LINE PASSING THROUGH THE POINTS (5,4) AND (-6.3) Y=

Sagot :

Crisforpidn
( x - 5) / ( -6 - 5) = (y - 4)/( 3 - 4) <=>  (x-5)/(-11) = (y-4)/(-1) <=> x - 5 = 11y - 44 <=>
 x - 11y + 39 = 0;
First you have to find the slope of the line.  
(y2 -y1) / (x2 - x1) = slope
 so (3 - 4) / ( -6 - 5)  = -1/ -11 so the slope of the line is 1/11

Now you write y = mx + b  then substitute in one of the points with x and y
                     4 = (1/11)(5) + b
                     4 = 5/11 + b 
                 -5/11= - 5/11       change the 4 into 44/ 11 and subtract
     44 / 11 - 5/11=         b
                39/11 =     b                          now it depends on your teacher and text
usually, you can substitute the fraction for your b
     y = mx + b
     y = 1/11 x + 39/11   so this is your answer

Does that make sense or did I make a mathematical error?

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