ProPeaceidn
Answered

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[tex]9X^2-12X+4=0[/tex] X=?

Sagot :

Konrad509idn
[tex]9x^2-12x+4=0\\ (3x-2)^2=0\\ 3x-2=0\\ 3x=2\\ x=\dfrac{2}{3} [/tex]
ValyRemusidn
[tex]9x^2-12x+4=0[/tex] 

[tex](3x)^2-2\cdot 2\cdot3x+2^2=0[/tex]

[tex](3x-2)^2=0, but...(3x-2)^2 \geq 0[/tex] , ∨ x∈R

[tex]So, (3x-2)^2=0[/tex]

[tex]3x-2=0[/tex] ⇒ [tex]3x=2[/tex] ⇒ [tex]\boxed { x= \frac{2}{3} }[/tex]
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