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Write the equation of a line that is perpendicular to the given line and that passes through the given point.

x + 8y = 27; (–5, 5)

a. y = 1/8x + 45
b. y = 8x + 45
c. y = -8x + 45
d. y = 1/8x - 45



Sagot :

IGreenidn
First, let's re-arrange to slope-intercept form.

x + 8y = 27

Subtract 'x' to both sides:

8y = -x + 27

Divide 8 to both sides:

y = -1/8x + 3.375

So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.

So the slope of the perpendicular line will be 8.

Now we can plug this into point-slope form along with the point given.

y - y1 = m(x - x1)

y - 5 = 8(x + 5)

y - 5 = 8x + 40

y = 8x + 45
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