Answered

IDNLearn.com is the perfect place to get detailed and accurate answers to your questions. Get step-by-step guidance for all your technical questions from our dedicated community members.

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

x + 8y = 27; (–5, 5)

a. y = 1/8x + 45
b. y = 8x + 45
c. y = -8x + 45
d. y = 1/8x - 45



Sagot :

IGreenidn
First, let's re-arrange to slope-intercept form.

x + 8y = 27

Subtract 'x' to both sides:

8y = -x + 27

Divide 8 to both sides:

y = -1/8x + 3.375

So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.

So the slope of the perpendicular line will be 8.

Now we can plug this into point-slope form along with the point given.

y - y1 = m(x - x1)

y - 5 = 8(x + 5)

y - 5 = 8x + 40

y = 8x + 45
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.