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solve and check
2/3y =6
A.1/9
B.1/4
C.9
D.4


Sagot :

[tex] \frac{2}{3} *y=6 \\ \\ y=6: \frac{2}{3} =6* \frac{3}{2} = \frac{18}{2} =9 [/tex]

So the answer is C. 9

2/3* 9=(2*9)/3=18/3= 6 (true)

[tex]\frac{2}{3}y=6\ \ \ \ |divide\ both\ sides\ by\ \frac{2}{3}\ /multiply\ by\ \frac{3}{2}/\\\\y=6\cdot\frac{3}{2}\\\\y=\frac{6}{1}\cdot\frac{3}{2}\\\\y=\frac{\not6^3\cdot3}{1\cdot\not2_1}\\\\y=\frac{3\cdot3}{1\cdot1}\\\\y=\frac{9}{1}\\\\\boxed{y=9}\leftarrow answer\ \boxed{C}[/tex]

[tex]check:\\\\/put\ the\ value\ of\ y=9\ to\ the\ equation\ \frac{2}{3}y=6/\\\\\frac{2}{3}\cdot9=6\\\\\frac{2}{3}\cdot\frac{9}{1}=6\\\\\frac{2}{\not3_1}\cdot\frac{\not9^3}{1}=6\\\\\frac{2}{1}\cdot\frac{3}{1}=6\\\\2\cdot3=6\\\\\boxed{6=6}\leftarrow TRUE[/tex]