Answered

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Complete by solving the square:

2x^2−9x+9=0

Sagot :

[tex]2( x^{2} -4.5x)+9=0[/tex]

[tex]2[(x-2.25) ^{2}-5.0625]+9=0 [/tex]

[tex]2(x-2.25) ^{2}-10.125+9=0 [/tex]

[tex]2(x-2.25) ^{2}-1.125=0 [/tex]

[tex](x-2.25) ^{2}=0.5625 [/tex]

[tex]x-2.25= \sqrt{0.5625} [/tex]

[tex]x-2.25=0.75[/tex]

[tex]x-2.25=-0.75[/tex]

[tex]x=3[/tex] or [tex]x=1.5[/tex]

Hope this helped

Panoyinidn
ax² + bx + c = 0
2x² - 9x + 9 = 0
2x² + (-9x) + 9 = 0
x = -b +/- √b² - 4ac
                2a
x = -(-9) +/- √9² - 4(2)(9)
                    2(2)
x = 9 +/- √81 - 72
               4
x = 9 +/- √9
           4
x = 9 +/- 3 
          4
x = 9 + 3    x = 9 - 3
         4                4
x = 12        x = 6
       4               4
x = 3          x = 3/2 or 1 1/2
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