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c=0.04x^2-8.504x+25302 how do i do this?

Sagot :

HeyDBidn
Solving for x.

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
0.04x2−8.504x+25302=c

Simplify the quadratic and set the right side equal to 0.
0.04x2−8.504x+25302−c=0

Use the standard form of the quadratic (ax2+bx+c) to find a,b, and c for this quadratic.
a=0.04,b=−8.504,c=25302−1c

Use the quadratic formula to find the solutions.
x=−b ± √ b2−4ac / 2a

Substitute in the values of a=0.04,b=−8.504, and c=25302−1c.
x=−(−8.504) ±√(−8.504)2−4(0.04)(25302−1c)/2(0.04)

Simplify.
x=8.504 ±√(−8.504)2−4(0.04)(25302−1c)/2(0.04)

Simplify the section inside the radical.
x=8.504 ± √−3976.001984+0.16c/2(0.04)

Simplify the denominator of the quadratic formula.
x=8.504 ±√−3976.001984+0.16c/0.08


Answer:
x=8.504 ±√−3976.001984+0.16c/0.08


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