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The area of a triangle is 24 square inches. The height is 4 inches shorter than the base. Find the height and the base of the triangle
area=24 height=base-4 1/2bh h=b-4 subitute b-4 for h 1/2b(b-4) 1/2(b^2-4b) 1/2(b^2-4b)=24 multiply by 2 b^2-4b=48 subtract 48 from both sdies b^2-4b-48=0 factor because if xy=0 then x or/and y=0
find what 2 numbers multiply to get -48 and add to get -4 the numbers are hard to find but they are -9.2111 and 5.2111
so (b-9.2111)(b+5.2111)=0 therefor b-9.2111=0 add 9.2111 b=9.2111 b+5.2111=0 subtract 5.2111 b=-5.2111 but since the measure can't be negative, we discard this solution
so base=9.2111 subsitute h=b-4 h=9.2111-4 h=5.2111
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