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Sagot :
First, we define the volume of a cone as V= 1/3x Pi x r²xH and the volume of a cylinder as v= Pi x R² x h. So, according to the question we have V=2/3v=(2/3)xR²xPixh=(2/3) x 3.14x5²x15=785cm^3. V=785cm^3. So it is (1/3) x3.14xr²xh=785, this implies r=10, and h=7.5, because (1/3) x3.14x100x7.5=785. Finally, the dimensions of the cone are r=10, h=7.5 and V=785cm^3
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