Khaliqnionsidn
Answered

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If n represents an odd integer,write expressions in terms of n that represents the next three consecutive odd integers.If the four consecutive odd integers have the sum of 56,find the numbers

Sagot :

N
N+2
N+4
N+6

That would be the answer for the first sequence.

Your second question--the integers would be 11,13,15, and 17
AL2006idn

Every second integer is odd.  (The ones in between them are even.)

If you promise that 'n' is odd, then the next odd ones
are (n+2), (n+4), and (n+6) .

We need to add them all up:

   n + (n+2) + (n+4) + (n+6)  =  4n + 12

Now you're telling me that the sum is 56.  Knowing that, I can
figure out what 'n' is, and once I know  'n', I can fiugure out all
four of the numbers.

                                           4n + 12 = 56

Subtract  12  from each side:      4n = 44

Divide each side by  4 :                 n = 11

The four consecutive odd integers are:

   n . . . . . 11
   n+2 . . . 13
   n+4 . . . 15
   n+6 . . . 17 .


Check the answer:

Add up  (11 + 13 + 15 + 17)  =   56          yay ! 


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