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Find two numbers whose product is -140 and sum is -4.



Sagot :

{xy=-140, x+y+4=0)
(xy=-140, y=-x-4)
x=10, y=-14
x=-14, y=10


[tex]\left\{\begin{array}{ccc}x\cdot y=-140\\x+y=-4& y=-x-4\end{array}\right\\\\substitute:\\\\x\cdot(-x-4)=-140\\-x^2-4x+140=0\\\\\Delta=(-4)^2-4\cdot(-1)+140=16+560=576;\ \sqrt\Delta=\sqrt{576}=24\\\\x_1=\frac{4-24}{2\cdot(-1})=\frac{-20}{-2}=10;\ x_2=\frac{4+24}{2\cdot(-1)}=\frac{28}{-2}=-14\\\\y_1=-10-4=-14;\ y_2=-(-14)-4=14-4=10\\\\Answer:10\ and\ -14.[/tex]