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If x is a real number such that x³ = 64, then x² + √x =?

Sagot :

Lilithidn
[tex]x^3 = 64\\ \\x=\sqrt[3]{64}\\ \\x=4 \\ \\ \\ x^2 + \sqrt{ x }=4^2+\sqrt{4}=16+2 =18[/tex]


Sitaraidn
If x³=64
,x=∛64=4
x²=16
√x=4
x²+√x=16+2
⇒18

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