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Consider the following equation:

4NH₄ + 5O₂ → 4 NO + 6H₂O

How many moles of water are produced when 2 moles of NH4 react with excess Oxygen gas?

Sagot :

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see we have two moles of NH4, so we replace 4 NH4 by 2 NH4.
Now, on balancing the equation, we get 2 NH4 + 3O2 ---> 2NO + 4 H2O (law of conservation of mass)
thus, 2 moles of NH4 react with 3 moles of oxygen gas to produce 2 moles of NO2 and 4 moles of H2O.
Thus, we get 4 moles of H2O 

4 NH4 + 5 O2 → 4 NO + 6 H2O  

(2 mol NH4) x (6 mol H2O / 4 mol NH4) = 3 mol H2O

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