At IDNLearn.com, find answers to your most pressing questions from experts and enthusiasts alike. Our platform is designed to provide trustworthy and thorough answers to any questions you may have.

what is the standard form of the equation for this circle 4, -5 radius 5.5

Sagot :

Standard form of equation of a circle:

(x - a)^2 + (y -b)^2  =  r ^2.

Where centre =  (a , b)
r  = radius.
Centre (4 , -5) = (a , b) ,  a = 4,  b = -5.
r = 5.5.

(x - 4)^2 + (y - -5)^2  = 5.5^2
(x - 4)^2 + (y +5)^2  = 5.5^2      Expand brackets, and use your calculator

x^2 - 8x + 16  +  y^2 +10y + 25 = 30.25 
x^2 - 8x +  y^2 +10y + 25 +16 - 30.25 = 0
x^2 - 8x +  y^2 +10y  - 10.25  = 0.   
x^2 + y^2 -8x +10y  - 10.25  = 0.       That's the equation of the circle.

or  10.25 =  10    /1/4  = 41/4

x^2 + y^2 -8x +10y  - 41/4  = 0    Multiply both sides of the equation by 4.

4x^2 + 4y^2 -32x +40y  - 41  = 0

Cheers.
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.