Expand your knowledge base with the help of IDNLearn.com's extensive answer archive. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.

Charlie is 24 years older than Marty. If the total years old of both are 130, find the years old of each one.

Sagot :


C- Charlie

M-Marty

C=24+M

C+M=130

_______

24+M+M=130

2M=106

M=53

C=53+24=77

C=77


[tex]x-Charlie\ age\\y-Marty\ age\\\\Chrlie\ is\ 24\ years\ older\ than\ Marty:x=y+24\\The\ total\ years\ old\ of\ both\ are\ 130:x+y=130\\\\Therefore\ we\ have:\\ \left\{\begin{array}{ccc}x=y+24&(1)\\x+y=130&(2)\end{array}\right\\\\subtitute\ (1)\ to\ (2):\\\\(y+24)+y=130\\y+24+y=130\\2y+24=130\ \ \ \ |subtract\ 24\ from\ both\ sides\\2y=106\ \ \ |divide\ both\ sdies\ by\ 2\\\boxed{y=53}[/tex]

[tex]Subtract\ the\ value\ of\ y=53\ to\ the\ (1):\\\\x=53+24=\boxed{77}\\\\\boxed{ \left\{\begin{array}{ccc}x=77\\y=53\end{array}\right}\\\\Answer:\\Charlie\ age:77\\Marty\ age:53[/tex]