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Complete the equation for the linear function whose graph contains the points
(9, 7) and (4, –8).


Complete The Equation For The Linear Function Whose Graph Contains The Points 9 7 And 4 8 class=

Sagot :

y-7=3(x-9) or it could be y=3x-20

Answer:

[tex]\boxed{\boxed{y-7=3(x-9)}}[/tex]

Step-by-step explanation:

The given points are [tex](9, 7),(4, -8)[/tex]

We can get the line equation passing through these points by applying point slope formula.

The slope of the line joining these two points would be,

[tex]=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]=\dfrac{-8-7}{4-9}[/tex]

[tex]=\dfrac{-15}{-5}[/tex]

[tex]=3[/tex]

The general point slope form of straight line is,

[tex]y-y_1=m(x-x_1)[/tex]

Putting the slope as 3 and the point as (9, 7),

[tex]y-7=3(x-9)[/tex]