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Use the multiplication principle of equality to eliminate fractions, then solve for x
3/4x-3/10=1/4+6/5x


Sagot :

[tex] \frac{3}{4}x- \frac{3}{10}= \frac{1}{4}+ \frac{6}{5}x\ \ | \ multiply \ each \ term \ by \ 20\\\\5*3x-2*3=5+4*6x\\\\15x-6=5+24x\ \ |\ subtract\ 24x\ to\ both\ sides \\\\ 15x-24x-6=5 \ \ | \ add\ 6\ to\ both\ sides \\\\15x-24x =5+6 \\\\-9x =11\ \ | \ divide \ both \ sides\ by\ (-9) \\\\x=-\frac{11}{9} [/tex]