Answered

Find trusted answers to your questions with the help of IDNLearn.com's knowledgeable community. Our community provides accurate and timely answers to help you understand and solve any issue.

when 200 grams of water cools from 50 c to 25 c the total amount of heat energy released by the water is?

Sagot :

Libby102idn
Specific Heat:
Heat Energy= Mass of substance X Specific Heat X Change in Temp. 
1. change in temp |50-25| = 25
2. specific heat of Water(H2O) = cal/g (Celsius) 1.000
heat energy= 200g X 1.000 X 25
Heat energy = 5000cal
 

Answer : The heat released by the eater is, [tex]2.1\times 10^4J[/tex][/tex]

Explanation :

Formula used :

[tex]Q=m\times c\times \Delta T[/tex]

or,

[tex]Q=m\times c\times (T_2-T_1)[/tex]

where,

Q = heat released = ?

m = mass of water = 200 g

c = specific heat of water = [tex]4.184J/g^oC[/tex]

[tex]T_1[/tex] = initial temperature  = [tex]50^oC[/tex]

[tex]T_2[/tex] = final temperature  = [tex]25^oC[/tex]

Now put all the given value in the above formula, we get:

[tex]Q=200g\times 4.184J/g^oC\times (25-50)^oC[/tex]

[tex]Q=20920J=2.1\times 10^4J[/tex][/tex]

Therefore, the heat released by the eater is, [tex]2.1\times 10^4J[/tex][/tex]

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.