Answered

IDNLearn.com makes it easy to find precise answers to your specific questions. Get prompt and accurate answers to your questions from our community of experts who are always ready to help.

when 200 grams of water cools from 50 c to 25 c the total amount of heat energy released by the water is?

Sagot :

Libby102idn
Specific Heat:
Heat Energy= Mass of substance X Specific Heat X Change in Temp. 
1. change in temp |50-25| = 25
2. specific heat of Water(H2O) = cal/g (Celsius) 1.000
heat energy= 200g X 1.000 X 25
Heat energy = 5000cal
 

Answer : The heat released by the eater is, [tex]2.1\times 10^4J[/tex][/tex]

Explanation :

Formula used :

[tex]Q=m\times c\times \Delta T[/tex]

or,

[tex]Q=m\times c\times (T_2-T_1)[/tex]

where,

Q = heat released = ?

m = mass of water = 200 g

c = specific heat of water = [tex]4.184J/g^oC[/tex]

[tex]T_1[/tex] = initial temperature  = [tex]50^oC[/tex]

[tex]T_2[/tex] = final temperature  = [tex]25^oC[/tex]

Now put all the given value in the above formula, we get:

[tex]Q=200g\times 4.184J/g^oC\times (25-50)^oC[/tex]

[tex]Q=20920J=2.1\times 10^4J[/tex][/tex]

Therefore, the heat released by the eater is, [tex]2.1\times 10^4J[/tex][/tex]

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.