Answered

IDNLearn.com provides a comprehensive platform for finding accurate answers. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.

Determine the second derivative of y=cosxtanx.

Thanks :)

Sagot :

[tex]f(x)=cosxtanx\\\\(cosxtanx)'=\left(cosx\cdot\frac{sinx}{cosx}\right)'=(sinx)'=cosx\\\\(cosx)'=-sinx\\\\f''(x)=-sinx\\\\\frac{\delta^2 f}{\delta x^2}=-sinx[/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.